C Squared

Alrighthen, vigorously, it's the acceleration of force that's actually work happening.

Omni, You are really deep into this now and I think you are missing my simple point or focus here because of math rules that are beyond real events. My simple point about the misuse of Planck is about time and units of time. Since h=6.6x10E-34js we can see this is energy times time and not energy times a unit of time. But, when the statement is: E=hf, the math is done in a way that time is replaced by a unit of time. This is like a card trick in real terms but maybe it is allowed in math rules. In any event the result is a bogus view of reality that is repeated over and over in QM. The simple fact is time and units of time are different and not interchangable as is the case here.

Can force be accelerated? So you have force times acceleration equals 6.6x10E-34watts times frequency? That is not correct is it?

Jim, I define 'time' as the calculus surrounding a 'particle' (or an event) whose position is time t given by x(t) (the basis for all mathematical applications) and I define 'units of time' as the base second (the theory used to measure the duration of all mathematical applications). So I define x(t) as real time, or work happening, and I define the second as Hawking's imaginary time, or the possibility of the duration it would take for work to happen.

So then E=hf should be solely based on the units of time because energy is the ability to do work thus E=hf would only be a possible theoretical measurment of the duration of the ability to do work, E=6.626x10^-34Js/s.

On the other hand Fa=hf would now be the actual application of work happening which means the calculus time comes into play assuming f=per x(t)and h=J[x(t)] when 'down reciprocated' is Fa=6.626x10^-34J/x^2(t^2).

Newton's 3rd Law explains that for every energetic photon action there's an equally imaginary energetic photon reaction (E=hf) and an oppositely real energetic photon reaction (Fa=hf).

Hence wave cone uncertainty E^2/hc>\/=h/16pi^2tq means real>\/=imaginary.

Newton's 3rd Law in terms of time is that for every temporal action there's an equally imaginary temporal reaction, t_s, and an oppositely real temporal reaction, x(t).

......................Om

As for the acceleration of force if m=E/v^2 then F=Ea/v^2 and Fv^2=Ea thus Fa=Ea/d which means Fa=E/t^2 just like we've been saying all along. The drivel would be that Power=Ea/v.

Omni, You posted above the statement: E=6.626x10^-34Js/s. What I take issue with is the two different ways "s" is used in that statement. You have "s/s" which in normal math is one. But in this case the upper "s" is an undetermined amount of time(maybe a nanosecond, a lightyear or whatever) and the lower "s" is a second of time or an exact amount of time. So, the result is not one unless it is made clear the upper "s" is one second of time. The upper "s" is where the confusion about the photon begins and when this is discovered by your people in control is will be astounding that such an error was never discovered before. But, that may not happen for a few centuries because of all the drivel believed to be important in models.