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C Squared
21 years 1 month ago #6655
by Jim
Replied by Jim on topic Reply from
I agree with you. There are a lot of ways to say something in math or English. What I mean is speed squared is not logical and acceleration is logical. It is not logical to assume energy and mass are united by square speed but it is logical that acceleration unites them. Only an opinion but it gets rid of a lot of stuff left over in the math. And then I don't know anything about why the math is held in so high a reguard so maybe I'm one of the empty minded trolls.
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21 years 1 month ago #6554
by Rahul
Replied by Rahul on topic Reply from Rahul Jain
<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by Jim</i>
<br />I agree with you. There are a lot of ways to say something in math or English. What I mean is speed squared is not logical and acceleration is logical. It is not logical to assume energy and mass are united by square speed but it is logical that acceleration unites them. Only an opinion but it gets rid of a lot of stuff left over in the math. And then I don't know anything about why the math is held in so high a reguard so maybe I'm one of the empty minded trolls.
<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">
Rahul Jain
Professional Computer Programmer
Amateur Theoretical Physicist
<br />I agree with you. There are a lot of ways to say something in math or English. What I mean is speed squared is not logical and acceleration is logical. It is not logical to assume energy and mass are united by square speed but it is logical that acceleration unites them. Only an opinion but it gets rid of a lot of stuff left over in the math. And then I don't know anything about why the math is held in so high a reguard so maybe I'm one of the empty minded trolls.
<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">
Rahul Jain
Professional Computer Programmer
Amateur Theoretical Physicist
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21 years 1 month ago #6555
by GD
Replied by GD on topic Reply from
Here is a quote from a physics book:
"A natural process that starts in one equilibrium state and ends in another will go in the direction that causes the entropy of the system plus environment to increase".
I still believe E=ma better describes nature. Water always flows downhill! The only natural way (without external forces) for matter to reverse direction is for it to convert into energy.
"A natural process that starts in one equilibrium state and ends in another will go in the direction that causes the entropy of the system plus environment to increase".
I still believe E=ma better describes nature. Water always flows downhill! The only natural way (without external forces) for matter to reverse direction is for it to convert into energy.
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21 years 1 month ago #6556
by Jan
Replied by Jan on topic Reply from Jan Vink
<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"> [GD:] I still believe E=ma better describes nature. Water always flows downhill! The only natural way (without external forces) for matter to reverse direction is for it to convert into energy.<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">
Personally, I like to think in terms of energy rather than velocities and accelerations: formulas such as F=m*a belong to the "direct methods" and are generally believed to be more involved, mainly because we are working with vectors rather than scalar quantities. Anyway, the validity of mathematical representations in physics need to be verified experimentally don't you think so? In the end, it doesn't really matter what representation we are using, as long as it serves our purpose. Hence, whatever describes nature better is the representation that matches our observations. If this is F=m*a, then that's fine, but if it is H=Kinetic+Potential, then I'm happy as well. [^]<font size="3"></font id="size3">
Personally, I like to think in terms of energy rather than velocities and accelerations: formulas such as F=m*a belong to the "direct methods" and are generally believed to be more involved, mainly because we are working with vectors rather than scalar quantities. Anyway, the validity of mathematical representations in physics need to be verified experimentally don't you think so? In the end, it doesn't really matter what representation we are using, as long as it serves our purpose. Hence, whatever describes nature better is the representation that matches our observations. If this is F=m*a, then that's fine, but if it is H=Kinetic+Potential, then I'm happy as well. [^]<font size="3"></font id="size3">
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21 years 1 month ago #6657
by Jim
Replied by Jim on topic Reply from
As a practical matter it makes no difference which process is used to determine an outcome so whatever works best seems a logical way to go about the business at hand. The reason the current theories need to be remodeled in my opinion is for quite different reasons than this. Anyway, about C^2, this constant makes no sense to me-what is square speed? Is it at all like square time or square meters?
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21 years 1 month ago #6775
by Jan
Replied by Jan on topic Reply from Jan Vink
<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote">[Jim:] Anyway, about C^2, this constant makes no sense to me-what is square speed? Is it at all like square time or square meters?<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">
You are thinking too deep, I think, which is a good thing by the way. [] The SOL "c" is a constant that we can live with, that is, it just has the unit of velocity [m/s], fair enough. On the other hand, c^2 has trivially the units [m^2/s^2], not very enlighting, but should it be viewed on its own? The formula E=m*c^2 has clearly the units of energy, thus [J]=[N]*[m]=[kg*m/s^2]*[m]= [kg]*[m^2/s^2]. So we see that the constant c^2 only makes sense in view of E=m*c^2. But I may have missed the point completely.
You are thinking too deep, I think, which is a good thing by the way. [] The SOL "c" is a constant that we can live with, that is, it just has the unit of velocity [m/s], fair enough. On the other hand, c^2 has trivially the units [m^2/s^2], not very enlighting, but should it be viewed on its own? The formula E=m*c^2 has clearly the units of energy, thus [J]=[N]*[m]=[kg*m/s^2]*[m]= [kg]*[m^2/s^2]. So we see that the constant c^2 only makes sense in view of E=m*c^2. But I may have missed the point completely.
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