Pushing gravity mechanics

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21 years 9 months ago #2783 by mechanic
Replied by mechanic on topic Reply from
Happy birthday to you Mac. As I suspected before there is a confusion between time and rate of fall evident in the writtings of that link. These are thoughts of a freshman level college kid in my opinion. Below is a link to a paper describing a scientific, "real" experiment:

www.aip.org/enews/physnews/1992/split/pnu094-1.htm

I just joinned another message board. The subjects are very interesting and people justisfy their positions one way or another, something not happening here at all. Thank you for your input and good luck with your work.

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21 years 9 months ago #4966 by Mac
Replied by Mac on topic Reply from Dan McCoin
mechanic,

Thanks for the link and birthday wish.

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21 years 9 months ago #4677 by Mac
Replied by Mac on topic Reply from Dan McCoin
mechanic,

I admit reading his presentation isn't that clear. But I had the opportunity to be involved on another message board where these issues were discussed and he clarified some of his points. In fact you may have noticed some of his experiments have switched between the graphics and the text.

But the primary one that I realized was this:

If you take two objects (spheres) the same size but of different densities or even the same density and test them individually you get one result.

BUT if you test them simultaneously you will get another result. The reason is that the commonly left out factor is the movement of the earth toward the free-falling mass(es). The earth applies the same effect to both masses either individualy or together but when tested together there are two masses affecting the earths reaction. Hence it moves faster, hence they arrive sooner, hence the rate has increased.

Having relized that one can see that more massive objects really do have a higher closing rate to the earth. The G constant hasn't changed and the individual F = ma is still intact but from a pragmatic view when the earths motion is considered, one measuring the time to reach earth heavier objects will appear to have a higher acceleration because they reach earth sooner, since the earth moved more toward them.

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21 years 9 months ago #4738 by Jim
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Mac, This is a result I posted here a week ago-can you comment on my question about temperature affecting gravity in any way? This was in reply to MV on 01-31-03 above. thanks

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21 years 9 months ago #4782 by 1234567890
Replied by 1234567890 on topic Reply from
<BLOCKQUOTE id=quote><font size=2 face="Verdana, Arial, Helvetica" id=quote>quote:<hr height=1 noshade id=quote>
mechanic,

I admit reading his presentation isn't that clear. But I had the opportunity to be involved on another message board where these issues were discussed and he clarified some of his points. In fact you may have noticed some of his experiments have switched between the graphics and the text.

But the primary one that I realized was this:

If you take two objects (spheres) the same size but of different densities or even the same density and test them individually you get one result.

BUT if you test them simultaneously you will get another result. The reason is that the commonly left out factor is the movement of the earth toward the free-falling mass(es). The earth applies the same effect to both masses either individualy or together but when tested together there are two masses affecting the earths reaction. Hence it moves faster, hence they arrive sooner, hence the rate has increased.

Having relized that one can see that more massive objects really do have a higher closing rate to the earth. The G constant hasn't changed and the individual F = ma is still intact but from a pragmatic view when the earths motion is considered, one measuring the time to reach earth heavier objects will appear to have a higher acceleration because they reach earth sooner, since the earth moved more toward them.


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The reason most high school physics teacher leave out "half of the equation" is because they are not dropping moon-sized balls from top of towers. It is self evident from Newton's gravitational force equation that more massive objects would have faster "closing" times than two objects of smaller total mass.

However, doesn't shape affect the rate of falling objects according to Newtons equation? An irregularly shaped mass with more mass at one end would probably generate a torque due to the unbalanced gravitational force, thus reaching a higher terminal velocity.

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21 years 9 months ago #3812 by Mac
Replied by Mac on topic Reply from Dan McCoin
Jim,

I don't have specfic information regarding heat affects on gravity however, heat was predicted as a by product in UniKEF and such heat flow from the earths core correlating to gravity potential has been found.

Also since heat induces increased motion of particles it follows that it should have an impact on gravity "orthogonal" to the particles motion. See UniKEF/Messages/Graphics/Fig_6.

It come to mind that this affect might permit a calculation regarding "Speed of Gravity". If temperature could be correlated to a change in gravittional force, then the speed of particles at various temperature temperatures may be able to be correlated trigometrically to the velocity of the field.


123...,

I don't think we have any disagreements here. The issue was the fact that the equal rate is preached so definitely as a LAW and disregards the fact that it only appears uniform for a limited range and that it actually varies is the point. In otherwords it is felt that we should be teaching the facts and qualifying the generic use of equal acceleration.

There are many things in physics that are more minute than this that we make to be very important and base whole concepts on. For example the difference in Newton Gravity and Relavistic gravity. YOu have to start to be picky to point out a difference but they turn around and just glaze over the fact that objects don't have common rates but say instead that they do when they don't, just because the difference is generally negligable.

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