The Theory of Invariance

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13 years 8 months ago #21145 by Stoat
Replied by Stoat on topic Reply from Robert Turner
Hi Marx, I think that if we have a countable infinity condense out of an uncountable infinity then we needn't think about negative time, where time is considered to be a fourth spacial dimension. I would argue that we simply don't have a metric of time at the moment (excuse the pun)

The two infinities are not the same "size," think of them as the real numbers and the natural numbers. One's quantised. In an expanding countable infinite universe, hbar taken as one gives us our level of quantisation but the value of hbar can increase over time, or the value of G can decrease over time. If the speed of light was very much faster, then we would not live in a relativistic e.m. universe, we don't live in a relativistic gravitational universe.

If the speed of gravity falls from infinity to some huge value, then e.m. matter can condense round proto gravitational matter. Now I think this grav matter has an angular momentum of one and the e.m matter surrounding it has an angular momentum of hbar. This would have an absurdly small Schwarzschild radius and a huge mass equivalent. An electron would have a gravitational mass of about 1.3 tonnes. However, it's so far away from the e.m. electron, that's its gravitational force on that mass is miniscule.

Right, so let's use a ratio of the speed of light squared, divided by the speed of gravity squared and then plug in the speed of light squared into the divisor. Call the speed of gravity b, and I think it's a good bet to say that the ratio is c^2 / b^2 = 1.045E-34
So, 1.045E-34 = v^2 /c^2 So v = 3.064E-9 metres per sec.

Well, suppose in a moment of madness I thought that actual people lived in this very very cold region of the universe. I want to try and talk to them, they live in a phase change part of my universe and their time is going to be different to mine. So i'd need to compress my message right down to the bone. That's tricky but I have to assume that their world is an anti mirror of my world. I'd send a half key code based on primes, and they send back the same message.

That may sound like a tautology but tautologies are not simple identities. I think what it boils down to, is that the universe is entangled with its future self. Where hbar or G or the speed of light are different, or potentially different. If it's self regulatory, then it could draw on energy from another possible universe and create virtual particle pairs of different masses for instance. Balance the books as it were, so that it could continue to exist through time. Oddly there's no "by its bootstraps" creation going on here, just the behavior of a countable (quantised) infinity.



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13 years 8 months ago #21148 by Bart
Replied by Bart on topic Reply from
In terms of "Water waves" : Consider the following:
- a closed container filled with water
- a piston in the middle of the container that is surrounded by the water

If we move the piston up:
- water right above and below the piston will move up
- the same amount of water will move down right next to the piston
- the energy put into the piston will be transferred to the water (and will not return to the piston to force it to move downwards again) which implies the creation of a wave within the water
- the energy (wave) will (also) distribute transverse to direction of the piston
- in water, the energy of the waves will be transformed directly to thermal energy
- in aether, the energy of the waves will not be transformed (as the aether is frictionless)

I initiated a separate topic "Stellar and Planetary aberration model" to provide evidence of the existance of an aether.

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13 years 8 months ago #21149 by Cindy
Replied by Cindy on topic Reply from
<font size="3"><b>Invariance - Doppler Effect</b></font id="size3">

In absolute space and time, Invariance state that equation of Doppler Effect of Light must be in form:

f/f<font size="1">o</font id="size1"> = <i>f</i>(v) = e^(kv)

because <i>f</i>(v) = 1/<i>f</i>(-v)
and <i>f</i>(2v) = <i>f</i>(v).<i>f</i>(v)

Compare the equation with real measurement, we get k = 1/c.

Hence,

1. In case of light source and observer are moving far away each other, f/f<font size="1">o</font id="size1"> = e^(-v/c).

2. In case of light source and observer are moving closer each other,
f/f<font size="1">o</font id="size1"> = e^(v/c).

Here,

f<font size="1">o</font id="size1"> is frequency of light emitted at the source.
f is frequency of light measured by the observer.
v is velocity between light source and observer.

In Invariance, velocity v can be greater than c. In other word, even the observer is moving away from a light source with a velocity v &gt; c, photons from the light source still hit him (*) in frequency f = f<font size="1">o</font id="size1">.e^(-v/c).

(*) Photons hit him at speed c. The equation satisfy the second postulate, which state that in vacuum, speed of light with respect to any observer is c.

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13 years 8 months ago #21155 by Cindy
Replied by Cindy on topic Reply from
Hi everyone,

So far, the theory of Invariance have given us two equations:

<b>1. Blue Shift, Red Shift:</b>

f = f<font size="1">o</font id="size1">.[e^(<u>+</u>gh/cc)]

<b>2. Doppler Effect</b>

f = f<font size="1">o</font id="size1">.[e^(<u>+</u>v/c)]

If there is no member who disagree about the two equations above, then I will continue to present Equivalence of Mass and Energy, a derivation of E = mcc, the equation of 20th century from Invariance.

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13 years 8 months ago #21157 by evolivid
Replied by evolivid on topic Reply from Mark Baker
Hey Stoat

I think your right about the universe entangled with its future self...
I think v/v = c/c =[dimensionless]= transmittance or absorbancy
v = velocity
v = [length][time]-1
c = speed of light
g = gravitational acceleration
g = [length][time]-2
c = [length][time]-1
c/g = [time]
and c/g = 3.057*10^7 seconds or 353.8 days

Cindy how would you use that equation to find a earth like planet
and can you use the elementary dimentions with your equations
so it can make it easyer to understand the blue and red shift?
Thankx Cindy

Cheers

MARX

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13 years 8 months ago #21158 by Cindy
Replied by Cindy on topic Reply from
Hi Evolivid,

Thanks for your reply,

Space and time in Invariance are Newtonian space and time, so they are very simple. About the blue shift experiment:

Experiment:

1. One photon with its energy E<font size="1">o</font id="size1">, measured at A in a uniform gravitation field g.

This photon is emitted straight down from A to B then to C with AB = BC = h.

Call E<font size="1">B</font id="size1">, energy of the photon measured at B, and
Call E<font size="1">C</font id="size1">, energy of the photon measured at C.

Because energy E of photon and height h are variable amounts, we can write ratio E/E<font size="1">o</font id="size1"> as a function <i>f</i> of height h:

<b>E/E<font size="1">o</font id="size1"> = <i>f</i>(h)</b>

From this general equation, going back to the experiment, we have:

E<font size="1">B</font id="size1">/E<font size="1">o</font id="size1"> = <i>f</i>(h), and
E<font size="1">C</font id="size1">/E<font size="1">B</font id="size1"> = <i>f</i>(h), and
E<font size="1">C</font id="size1">/E<font size="1">o</font id="size1"> = <i>f</i>(2h)

Hence, we have <i>f</i>(2h) =<i> f</i>(h).<i>f</i>(h)

2. Now if we emit the photon upward in the gravitation field from C to B then to A, with the general equation above, we can write:

E<font size="1">B</font id="size1">/E<font size="1">C</font id="size1"> = <i>f</i>(-h)

Compare this equation to the middle equation in part 1, we get

<i>f</i>(h) = 1/<i>f</i>(-h)

3. Now we consider function <i>f</i>(h). It is a function with:

<i>f</i>(h) = 1/<i>f</i>(-h), and
<i>f</i>(2h) = <i>f</i>(h).<i>f</i>(h)

Therefore, function <i>f</i>(h) is an exponent function:

<i>f</i>(h) = e^(kh)
E/E<font size="1">o</font id="size1"> = e^(kh)

4. We compare ratio E/E<font size="1">o</font id="size1"> = e^(kh) with values from real measurements, which yield E/E<font size="1">o</font id="size1"> <u>~</u> 1 + gh/cc. We get k = g/cc.

Because, energy E of a photon equals to multiply of its frequency with Planck's constant, the blue shift equation has been established:

<b>f/f<font size="1">o</font id="size1"> = e^(gh/cc)</b>, and

Red shift equation is:

<b>f/f<font size="1">o</font id="size1"> = e^(-gh/cc)</b>

In cases of gravitation fields of planets or stars,...gravitation fields g are figured out from gavitational constant G, mass M and distance R.

theoryofinvariance.blogspot.com/

Thank you so much for your reading of the theory of Invariance.


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