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C Squared
21 years 2 months ago #6723
by Mac
Replied by Mac on topic Reply from Dan McCoin
GD,
It doesn't matter if you accept "Pushing Gravity" as a concept or not but this site by TVF supports that view and a boo by that title is available. UniKEF is my work which is far less developed than "Pushing Gravity" but none the less is a pushing gravity concept.
The term has to do with gravity being a mechanical function of external energy transfer by absorbtion and/or attentuation vs the Newtonian view of every mass attracts everyother mass (by some mysterious force or property of matter) or by curved space (which also fails to provide a cause).
Knowing to believe only half of what you hear is a sign of intelligence. Knowing which half to believe can make you a genius.
It doesn't matter if you accept "Pushing Gravity" as a concept or not but this site by TVF supports that view and a boo by that title is available. UniKEF is my work which is far less developed than "Pushing Gravity" but none the less is a pushing gravity concept.
The term has to do with gravity being a mechanical function of external energy transfer by absorbtion and/or attentuation vs the Newtonian view of every mass attracts everyother mass (by some mysterious force or property of matter) or by curved space (which also fails to provide a cause).
Knowing to believe only half of what you hear is a sign of intelligence. Knowing which half to believe can make you a genius.
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21 years 2 months ago #6622
by Jim
Replied by Jim on topic Reply from
The use of square mass or square velocity seems like a good way to solve math problems much like using things like the square root of minus one or other such things. The problem I see with C^2 is the exact value assigned to it. Would there be a need for inventing particles if that value was not fixed as it is? Do you need a neutrino if C^2 was changed to suit the need that exists for it?
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21 years 2 months ago #6623
by Mac
Replied by Mac on topic Reply from Dan McCoin
Jim,
I personally share the idea that c^2 is a somewhat arbitrary number and I'm reasonably sure it has not be emperically verified as being an exact fit for reality. I can see v^2 more readily in energy conversion than I could mass squared in gravity. Once a pushing type gravity concept developed in my mind then the mass squared made sense as being an indirect measure of the absorbtion or transfer coefficient of a kenetic energy driving source.
Knowing to believe only half of what you hear is a sign of intelligence. Knowing which half to believe can make you a genius.
I personally share the idea that c^2 is a somewhat arbitrary number and I'm reasonably sure it has not be emperically verified as being an exact fit for reality. I can see v^2 more readily in energy conversion than I could mass squared in gravity. Once a pushing type gravity concept developed in my mind then the mass squared made sense as being an indirect measure of the absorbtion or transfer coefficient of a kenetic energy driving source.
Knowing to believe only half of what you hear is a sign of intelligence. Knowing which half to believe can make you a genius.
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21 years 2 months ago #6678
by GD
Replied by GD on topic Reply from
In order to validate the assumptions concerning accelerating bodies and the relationship between c^2 and energy, a few observations on the dynamics of our solar system would have to be made:
As the solar system's linear velocity increases,
- does the orbiting speed of the planets decrease?
- are the orbits more elliptical?
- has there been a change in its trajectory and is now pointing towards the center of the galaxy?
- is Jupiter closest to the Sun?
- is there a noted increase in global warming?
As the solar system's linear velocity decreases,
- does the orbiting speed of the planets increase?
- are the orbits more circular?
- has there been a change in its trajectory and is now pointing away from the center of the galaxy?
- is Jupiter farthest from the Sun?
- is there a sustained decrease in global temperatures?
As the solar system's linear velocity increases,
- does the orbiting speed of the planets decrease?
- are the orbits more elliptical?
- has there been a change in its trajectory and is now pointing towards the center of the galaxy?
- is Jupiter closest to the Sun?
- is there a noted increase in global warming?
As the solar system's linear velocity decreases,
- does the orbiting speed of the planets increase?
- are the orbits more circular?
- has there been a change in its trajectory and is now pointing away from the center of the galaxy?
- is Jupiter farthest from the Sun?
- is there a sustained decrease in global temperatures?
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21 years 2 months ago #6681
by Samizdat
Replied by Samizdat on topic Reply from Frederick Wilson
<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by Quantum_Gravity</i>
<br />go to the third page on paradoxes and dilemas
[quote:
"E is equal to m c-squared, in which energy is put equal to mass, multiplied by the square of the velocity of light"
square of the velocity of light = (velocity of light ) * (velocity of light )= (3 * 10^9 m/s) * (3 * 10^9 m/s)= 9 * 10^18 m^2/s^2= c^2
That what Einstein told and the unit are m^2/s^2 (not a speed)
If you consider c as a vector c^2 is a scalar.
What is the problem?
The intuitive mind
<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">
All due respect, my phellow physics buffs, but this thread should have ended with the quote above.
<br />go to the third page on paradoxes and dilemas
[quote:
"E is equal to m c-squared, in which energy is put equal to mass, multiplied by the square of the velocity of light"
square of the velocity of light = (velocity of light ) * (velocity of light )= (3 * 10^9 m/s) * (3 * 10^9 m/s)= 9 * 10^18 m^2/s^2= c^2
That what Einstein told and the unit are m^2/s^2 (not a speed)
If you consider c as a vector c^2 is a scalar.
What is the problem?
The intuitive mind
<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">
All due respect, my phellow physics buffs, but this thread should have ended with the quote above.
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21 years 2 months ago #6687
by Jan
Replied by Jan on topic Reply from Jan Vink
<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by Samizdat</i>
<br /><blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by Quantum_Gravity</i>
<br />go to the third page on paradoxes and dilemas
[quote:
"E is equal to m c-squared, in which energy is put equal to mass, multiplied by the square of the velocity of light"
square of the velocity of light = (velocity of light ) * (velocity of light )= (3 * 10^9 m/s) * (3 * 10^9 m/s)= 9 * 10^18 m^2/s^2= c^2
That what Einstein told and the unit are m^2/s^2 (not a speed)
If you consider c as a vector c^2 is a scalar.
What is the problem?
The intuitive mind
<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">
All due respect, my phellow physics buffs, but this thread should have ended with the quote above.
<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">
Hi Samizdat,
Well, the problem is that if c is a vector then c^2 is not a scalar unless you have defined c^2:=<c,c>=sqrt(c1*c1+...+cn*cn). Thus, you have defined an inner product on an n-dimensional vector space E over the field R. An inner product is a linear map <.,.>: E x E --> R.
Of course, we can define an inner product over the complex numbers as well, but we are talking about the SOL constant "c", which is a real number. Now, the expression E=mc^2 is not a vector expression at all since "c" is the light speed, a magnitude, not a vector.
Just to make sure that we define our terminology rigorously. []
<br /><blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by Quantum_Gravity</i>
<br />go to the third page on paradoxes and dilemas
[quote:
"E is equal to m c-squared, in which energy is put equal to mass, multiplied by the square of the velocity of light"
square of the velocity of light = (velocity of light ) * (velocity of light )= (3 * 10^9 m/s) * (3 * 10^9 m/s)= 9 * 10^18 m^2/s^2= c^2
That what Einstein told and the unit are m^2/s^2 (not a speed)
If you consider c as a vector c^2 is a scalar.
What is the problem?
The intuitive mind
<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">
All due respect, my phellow physics buffs, but this thread should have ended with the quote above.
<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">
Hi Samizdat,
Well, the problem is that if c is a vector then c^2 is not a scalar unless you have defined c^2:=<c,c>=sqrt(c1*c1+...+cn*cn). Thus, you have defined an inner product on an n-dimensional vector space E over the field R. An inner product is a linear map <.,.>: E x E --> R.
Of course, we can define an inner product over the complex numbers as well, but we are talking about the SOL constant "c", which is a real number. Now, the expression E=mc^2 is not a vector expression at all since "c" is the light speed, a magnitude, not a vector.
Just to make sure that we define our terminology rigorously. []
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