Large Hadron Collider

That radius for the hemisphere is way too small. I had to up it by a billion to make it about a hundreth of the nucleus size. I kept the same gap width but it could go smaller. Then I get a force of
4 * 10^17 tonnes [][][8D] That is just unbelievable. If the gap was zero then our pushing particles would have a speed of infinity, and our quarks would be infinitely tough. So a quark simply cannot be totally opaque.

The trouble is, the more I read about the very strange zoo of supersymmetry (how does a selysium grab peope?) the more I'm reminded of the story of stone soup. A tramp asks for a stone to make some soup. Then he boils it up, and asks for a few things to give it a bit more flavour. People bring him salt, herbs, vegables and finally some meat. The people all marvel at how good stone soup tastes []

Sloat, You have more issues here than can be addressed but what about my question about the mass of the Z particle's fate? You seem to make a clear separation between force and energy some of the time and not all of the time. Why is this a part of your story?

Hey guys, there has had to be some editting in this thread for language and nonsense. can we chill it down some. Your friendly neighborhood moderator.

Mark Vitrone

Mark, are you saying you want this closed down?

Hmm... I just did the sums for the cassimer effect on two quarks. Going back to the figure of 15 tonnes of force. When the separation is h, the radius of the hemispherical quark is about 20 billion times smaller than h.

I suggested earlier that a Le Sage shadow is the first string theory but with this we might as well say that the shadow is a one dimensional string. That's an intriguing thought. I wonder why string theorists have never mentioned Le Sage.

Can anyone check my sums? My calculator wouldn't do anything with an index of 124.

A few more thoughts on this. The two quarks that make up a meson have different "masses." We have an up quark and anti down quark, which are at 0.004 and 0.008 Gev.

This shadow tube excludes all electromagnetic forces. It has to be at absolute zero. We know where it is, so we can't say anything about the momentum of its ends.

The two quarks will have major entropy problems. A hemisphere face is at absolute zero. One will want to "rob out" the other. But how can they? The only energy they could possibly use to do so has to be able to move in the shadow region.

Let's say that the quarks are not totally opaque to ftl particles. A few of these can be in the shadow. This might explain why the gravitational force looks so small. It's confined to a shadow slug that looks like a one dimensional string.

So let's have h for sub light and something ten billion times smaller for ftl. Then we can use hf = mc^2 to try and find the speed of gravity indirectly.

(Edited) A little more. The centre of gravity of a meson is always inside the shadow. Mesons are unstable. The three quark set ups is stable, the centre of gravity is always outside the shadow.

Allow ourselves complex solutions, and we can consider the shadow as a tube. We could then twang it like a guitar string. Perhaps then the centre of gravity of a proton say, could fall into a shadow. Though the string would very quickly set up a standing wave and damp out to somewhere where it should be. It might be fun to see how such a three stringed instrument might sound.Twang one and the other two would vibrate.