Pushing gravity mechanics

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21 years 10 months ago #4776 by tvanflandern
<BLOCKQUOTE id=quote><font size=2 face="Verdana, Arial, Helvetica" id=quote>quote:<hr height=1 noshade id=quote>[mechanic]: I now align both along their height and let them drop. Obviously, the area of the fat cylinder getting gravitons from the top is much larger than the area of the slim cylinder. How can it be true both cylinders dropping at the same rate all along the way?<hr height=1 noshade id=quote></BLOCKQUOTE id=quote></font id=quote><font face="Verdana, Arial, Helvetica" size=2 id=quote>

All other forces of nature operate on the surfaces of bodies and must be transmitted throughout the interior by molecule-to-molecule contact in response to a pressure wave. That is why they have the property called "inertia": The original force must be divided up or diluted among all the atoms of the body, and each must be set into motion. If the force is applied to (say) 100 atoms and the body has a billion atoms (not realistic numbers, but you get the idea), then the momentum transfered to the 100 atoms must be divided up a billion ways, resulting in a small forward motion. With a bigger body and more atoms, the same force yields even less motion.

Now consider the situation for gravity. Almost all gravitons can fly through the entire Earth without noticing. Only the occasional graviton actually hits something. So every individual atom of a body is just as accessible to a graviton impact as any other atom. But if there is an asymmetry in the graviton stream (as might be caused by being in the graviton shadow of a nearby mass), that produces a graviton wind "downward" into the shadow.

Your cylinders are small bodies in a graviton wind downward toward the Earth's surface (because the Earth blocks a small percentage of the upward-bound gravitons). Each cylinder has the same number of atoms by construction. And so each cylinder is struck just as often and just as hard by the net downward graviton wind. No atom has to share its momentum with any other atom because all atoms are receiving identical momentum impulses from the graviton wind. So both cylinders accelerate at the same rate because they have the same number of atoms (shape doesn't matter) and receive the same total momentum, which does not need to be divided up at all.

This answers your question. And as a bonus, it explains why surface area is never a factor in gravitation (surface atoms are no more or less likely to be struck than interior atoms). It also explains why gravity has no inertia -- i.e., why acceleration in a given gravitational field is the same for all bodies, big or small, and is therefore independent of the mass of the target body (because the applied momentum does not get diluted by sharing). It also explains why we don't feel the force of gravity when we are in free fall (no pressure wave between our atoms, so there is nothing to feel).

That's how it is in physics. When you have the wrong model, every new fact produces a new puzzle needing "explaining", usually with an add-on helper hypothesis. When you have the right model, all the answers to every question are already there just waiting for us to grow smart enough to notice. -|Tom|-

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21 years 10 months ago #4853 by mechanic
Replied by mechanic on topic Reply from
Thank you. You explanation in this context makes sense.

From Tom:

No atom has to share its momentum with any other atom because all atoms are receiving identical momentum impulses from the graviton wind. So both cylinders accelerate at the same rate because they have the same number of atoms (shape doesn't matter) and receive the same total momentum, which does not need to be divided up at all.


What about if I replace one cylinder with an equivalent mass of a heated liquid where atoms are forced to collide and exchange momentum? (like boiling water) What is the mechanism that differentiates graviton momentum from intrnal momentum transfer while dropping and cooling at the same time?





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21 years 10 months ago #4854 by tvanflandern
<BLOCKQUOTE id=quote><font size=2 face="Verdana, Arial, Helvetica" id=quote>quote:<hr height=1 noshade id=quote>What about if I replace one cylinder with an equivalent mass of a heated liquid where atoms are forced to collide and exchange momentum? (like boiling water) What is the mechanism that differentiates graviton momentum from internal momentum transfer while dropping and cooling at the same time?<hr height=1 noshade id=quote></BLOCKQUOTE id=quote></font id=quote><font face="Verdana, Arial, Helvetica" size=2 id=quote>

Each and every atom receives the same acceleration due to the local graviton wind. It does not matter whether those atoms are part of a body or are free and independent -- the acceleration due to gravity is the same either way.

Other forces of the conventional variety then simply add (vectorially) to the gravitational force. The result is identical to what you would predict by simply applying Newton's law without knowing about "pushing gravity". -|Tom|-

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21 years 10 months ago #4953 by mechanic
Replied by mechanic on topic Reply from
From Tom:

Each and every atom receives the same acceleration due to the local graviton wind. It does not matter whether those atoms are part of a body or are free and independent -- the acceleration due to gravity is the same either way.


Why wouldn't the extra momentum due to gravitons result in an increase in temperature or entropy in general than in a downward momentum for the liquid?

Your decomposition of the force vectors assumes a mechanism for differentiating them, which I can't see a physical process for, although it is possible doing in mathematical models. Momentum is what causes both heating and falling, isn't it?



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21 years 10 months ago #4539 by tvanflandern
<BLOCKQUOTE id=quote><font size=2 face="Verdana, Arial, Helvetica" id=quote>quote:<hr height=1 noshade id=quote>Why wouldn't the extra momentum due to gravitons result in an increase in temperature or entropy in general than in a downward momentum for the liquid?<hr height=1 noshade id=quote></BLOCKQUOTE id=quote></font id=quote><font face="Verdana, Arial, Helvetica" size=2 id=quote>

Bodies (solid, liquid, or gaseous) do not increase their temperatures as they free-fall. If each atoms receives an identical momentum, then relative motion and entropy are both unchanged.

<BLOCKQUOTE id=quote><font size=2 face="Verdana, Arial, Helvetica" id=quote>quote:<hr height=1 noshade id=quote>Your decomposition of the force vectors assumes a mechanism for differentiating them, which I can't see a physical process for, although it is possible doing in mathematical models. Momentum is what causes both heating and falling, isn't it?<hr height=1 noshade id=quote></BLOCKQUOTE id=quote></font id=quote><font face="Verdana, Arial, Helvetica" size=2 id=quote>

I'm not sure what you are getting at. If you are thinking that gravitons produce significant heating, that is not the case. Even for a body as big as the whole Earth, the excess heat is less than 1/1000 of the arriving solar energy. On a small body, this heat excess would be immeasurably small. -|Tom|-

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21 years 10 months ago #4540 by dholeman
Replied by dholeman on topic Reply from Don Holeman
<BLOCKQUOTE id=quote><font size=2 face="Verdana, Arial, Helvetica" id=quote>quote:<hr height=1 noshade id=quote> If you are thinking that gravitons produce significant heating, that is not the case. Even for a body as big as the whole Earth, the excess heat is less than 1/1000 of the arriving solar energy.
<hr height=1 noshade id=quote></BLOCKQUOTE id=quote></font id=quote><font face="Verdana, Arial, Helvetica" size=2 id=quote>

How, then, do planets explode?



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