Theory of Replication

Sloat, The joule is made of mc^2 not h. h is j times time thats the difference. h is joules times time and f is frequency that is added in after h has been established to be joule.time. What is commonly done is to assume time is one second and "therein lies the rub".

I think I found how the electrons and positrons reduce there mass .. m = f/a ! If we increase the acceleration of the orbital we can reduce the mass and I think that the "radius of the orbit at the speed of light" is "equal to or less then the mass radius of the electron spinning at the speed of light" or at electron rest (lack of a proton to orbit) and so the big question here is what is it orbiting now? ...I need to do some more work here.. looks like its, its own gravitational center that it is orbiting along with other positrons and electrons...

MARX

Here is another equation that has more to do with the mass reduction u,= M[a]*M(M[a]+M)^-1
where M[a] is mass a and M is mass b and u,= reduced mass

9.10938215`*^-31*9.10938215`*^-31 (9.10938215`*^-31 + 9.10938215`*^-31)^-1 = 4.554691074999999*10^-31

I got this equation from a book called "Methods in computational chemistry" molecular vibrations.
I got the editorial copy some how.. edited by Stephen Wilson

MARX

Hi Marx, can you post how that equation was derived.

hey Stoat the electronic motion [-(2u,)^-1DELTA^2+U(R)] = E electron where U is the potential energy curve E total = E electron + E nuclear , (motion) R is the internuclear separation it is part of the Schrodinger equation for nuclear motion I fried my laptop so im useing my PSP until I get a wifi card so my posts will be limited since the keyboard is virtual. I do have some models of the epe and there orbits I will post soon aps

MARX

Hi Marx, does this program mathematica do stuff like (1 - h ) / h
Using only a pocket calculator I just have to take that as the reciprocal of h but it's not quite that.

The way I see it, an electron is like a tiny bathysphere in a vaacuum sea. The pressure it's under is tremendous. So in its core it has a lump of spinning vacuum. This stops it from being crushed into nothingness. So the energy of the particle is not distributed half and half. The core, spinning much faster than light, has the lion's share of the kinetic energy.

In terms of my proposed speed of gravity, we look at this energy distribution in terms of the electron's frequency, as the gravitational energy is the same number as the e.m. frequency of the particle.

I get, grav energy = mc^2 + ((1 - h ) / h ) m c^2

mc^2 being the potential energy available to do work in our kind of e.m. space