My pareidolia knows no bounds.

<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by Marsevidence01</i>
<br />
Rich, well I am following to some degree but I think I will need some practice at this.

Would you have the time to advise on a "work in process"? I have posted and cropped image here

Parent image) www.uahirise.org/ESP_013772_1795 JPEG2000

Malcolm Scott
<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">
Well, as long as you maintained 100% <b>and </b>they gave you the pixel size (same in X and Y), all you need to know is:

How many pixels? Then it's just multiplication.

If I save this image and do it myself, we're at the mercy of me not knowing for sure if I'm dealing with 100% resolution in my final product, unless I download the image and do the whole thing myself.

Does the program you're using allow you to see the x,y pixel location as you move the cursor around? In Paint Shop Pro, regardless of what tool you're using, the status bar in the lower right shows the pixel location. So all you would have to do is point to one location you want to measure from, note the x,y pixel (say something like x:277, y:484) or whatever.

Then point to the other location, and you now have enough to work with. Do you remember the Pythagorean Theorem?


<ul><li> <b>a^2 + b^2 = c^2</b> </li></ul>





en.wikipedia.org/wiki/Pythagorean_theorem



rd

<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by Marsevidence01</i>
<br /> was wondering if you could ascertain the distance from right to left of these squares for me?

Malcolm Scott
<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote"> Plus, I'm not exactly sure what you mean by this anyway.

rd

<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by Larry Burford</i>
<br />Very cool. It is geographically associated with the Valles Marineris and other related features. Thanks.

Do you know Tom's theory about how this network of canyons were formed, and why they were (perhaps had to be) formed <u>here</u> instead of somewhere else on Mars?

LB
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Yes, I am somewhat familiar regarding the exploding nearby planet theory, one which I too subscribe also. It seems to make a lot of sense to me considering the topographical evidence on one hemisphere compared to the other. My big question is; can this event be accurately dated with any real certainty.

Malcolm Scott

<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by rderosa</i>
<br /><blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by Marsevidence01</i>
<br /> was wondering if you could ascertain the distance from right to left of these squares for me?

Malcolm Scott
<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote"> Plus, I'm not exactly sure what you mean by this anyway.

rd
<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">

Ok, I'll give this bash. Yes remember the Pythagorean theorem, just been a while since I put this to use.

Sorry, a bit misleading there, I was looking for the approximate distance in kilometers of the width of the square. A square was a little more noticeable that a line.

Thanks anyway

Malcolm Scott

<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by Marsevidence01</i>
<br />I was looking for the approximate distance in kilometers of the width of the square. A square was a little more noticeable that a line.

Malcolm Scott
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Oh. Well, that's even easier. Just find the number of pixels from one side of the square to the other.

By the way, I installed HiView and figured it out again. I had downloaded ESP_011359_1695_RED.JP2 (1.5Gb) last week, and I loaded it into HiView. I remember how to save crops again, but I would need a roadmap to ever find that Caveman. Is there an easy way to describe it? Seems like a needle in a haystack to me.

rd

<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by rderosa</i>
<br /><blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by Marsevidence01</i>
<br />I was looking for the approximate distance in kilometers of the width of the square. A square was a little more noticeable that a line.

Malcolm Scott
<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">
Oh. Well, that's even easier. Just find the number of pixels from one side of the square to the other.

By the way, I installed HiView and figured it out again. I had downloaded ESP_011359_1695_RED.JP2 (1.5Gb) last week, and I loaded it into HiView. I remember how to save crops again, but I would need a roadmap to ever find that Caveman. Is there an easy way to describe it? Seems like a needle in a haystack to me.

rd
<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">

Rich, the best way I think, is to view my video as this shows the caveman location quite well. He is located at the very bottom left hand corner of the image file. Here's the link for the video again. Best views in 1080 HD

drive.google.com/file/d/0B--tam0uh-oiS1R...NVk/edit?usp=sharing

Malcolm Scott