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Diurnal Variation of Earth's Rotation
- tvanflandern
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21 years 10 months ago #4559
by tvanflandern
Reply from Tom Van Flandern was created by tvanflandern
<BLOCKQUOTE id=quote><font size=2 face="Verdana, Arial, Helvetica" id=quote>quote:<hr height=1 noshade id=quote>[Jeremy]: Most theories I have seen like to say that mass "induces" onto the Earth or that Lorentz gravitational contractions occurs.<hr height=1 noshade id=quote></BLOCKQUOTE id=quote></font id=quote><font face="Verdana, Arial, Helvetica" size=2 id=quote>
You've been reading bad theories. <img src=icon_smile_sad.gif border=0 align=middle> Seriously, until about the mid-1980s, it was taught and believed that mass increased with speed in SR. But the interpretation of SR changed in the mid-1980s, for the 4th time since 1905. It is now understood that nothing happens to rest mass (real, physical mass represented by a count of nucleons). Instead, "relativistic mass" (gamma*m) and momentum (gamma*m*v) increase with speed by the relativistic gamma factor.
In the case of Earth's rotation, as Earth's relativistic mass (representing part of its increased orbital momentum) increases, its spin rate decreases to keep the spin momentum constant.
<BLOCKQUOTE id=quote><font size=2 face="Verdana, Arial, Helvetica" id=quote>quote:<hr height=1 noshade id=quote>How does the meta model or pushing theory in general explain the variation in angular momentum that occurs for the diurnal variation of rotation?<hr height=1 noshade id=quote></BLOCKQUOTE id=quote></font id=quote><font face="Verdana, Arial, Helvetica" size=2 id=quote>
MM agrees with the math of what is happening here. But MM has an explanation that provides a few more details. The increased density of the elysium (arising partly from Earth being closer to the Sun, partly from Earth's orbital speed being faster) makes electrons slow in their orbits, as expected for any wave-like entity when its medium gets denser. The slower the electrons move, the slower the body moves. The orbital slowing produces perihelion advance. The spin slowing produces the longer day you mentioned.
When the math is done in detail, it all works out. Those details (for the orbit, at least) appeared in <i>Meta Research Bulletin</i>, v. 8, pp. 10-15 & 24-30 (1999). Given those precepts, it would be easy to get a similar result for the spin. -|Tom|-
You've been reading bad theories. <img src=icon_smile_sad.gif border=0 align=middle> Seriously, until about the mid-1980s, it was taught and believed that mass increased with speed in SR. But the interpretation of SR changed in the mid-1980s, for the 4th time since 1905. It is now understood that nothing happens to rest mass (real, physical mass represented by a count of nucleons). Instead, "relativistic mass" (gamma*m) and momentum (gamma*m*v) increase with speed by the relativistic gamma factor.
In the case of Earth's rotation, as Earth's relativistic mass (representing part of its increased orbital momentum) increases, its spin rate decreases to keep the spin momentum constant.
<BLOCKQUOTE id=quote><font size=2 face="Verdana, Arial, Helvetica" id=quote>quote:<hr height=1 noshade id=quote>How does the meta model or pushing theory in general explain the variation in angular momentum that occurs for the diurnal variation of rotation?<hr height=1 noshade id=quote></BLOCKQUOTE id=quote></font id=quote><font face="Verdana, Arial, Helvetica" size=2 id=quote>
MM agrees with the math of what is happening here. But MM has an explanation that provides a few more details. The increased density of the elysium (arising partly from Earth being closer to the Sun, partly from Earth's orbital speed being faster) makes electrons slow in their orbits, as expected for any wave-like entity when its medium gets denser. The slower the electrons move, the slower the body moves. The orbital slowing produces perihelion advance. The spin slowing produces the longer day you mentioned.
When the math is done in detail, it all works out. Those details (for the orbit, at least) appeared in <i>Meta Research Bulletin</i>, v. 8, pp. 10-15 & 24-30 (1999). Given those precepts, it would be easy to get a similar result for the spin. -|Tom|-
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21 years 10 months ago #3846
by jacques
Replied by jacques on topic Reply from
<BLOCKQUOTE id=quote><font size=2 face="Verdana, Arial, Helvetica" id=quote>quote:<hr height=1 noshade id=quote> It is a well measured fact that the Earth's rate of rotation slows down as it approaches the Sun and that it speeds up as it moves away from the Sun. <hr height=1 noshade id=quote></BLOCKQUOTE id=quote></font id=quote><font face="Verdana, Arial, Helvetica" size=2 id=quote>
First time I hear that!
Can you give some sources?
First time I hear that!
Can you give some sources?
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21 years 10 months ago #4441
by Jeremy
Replied by Jeremy on topic Reply from
<BLOCKQUOTE id=quote><font size=2 face="Verdana, Arial, Helvetica" id=quote>quote:<hr height=1 noshade id=quote>
MM agrees with the math of what is happening here. But MM has an explanation that provides a few more details. The increased density of the elysium (arising partly from Earth being closer to the Sun, partly from Earth's orbital speed being faster) makes electrons slow in their orbits, as expected for any wave-like entity when its medium gets denser. The slower the electrons move, the slower the body moves. The orbital slowing produces perihelion advance. The spin slowing produces the longer day you mentioned.
<hr height=1 noshade id=quote></BLOCKQUOTE id=quote></font id=quote><font face="Verdana, Arial, Helvetica" size=2 id=quote>
So are you saying that the elysium is acting as a storage medium for the difference, that it is acting like a contracted spring that returns the momentum as the Earth goes around? Do the attractions between the atoms increase slightly and reduce the radius of the Earth?
<BLOCKQUOTE id=quote><font size=2 face="Verdana, Arial, Helvetica" id=quote>quote:<hr height=1 noshade id=quote>
First time I hear that! Can you give some sources?
<hr height=1 noshade id=quote></BLOCKQUOTE id=quote></font id=quote><font face="Verdana, Arial, Helvetica" size=2 id=quote>
The Pushing Gravity book discusses the magnitude of the effect but I imagine it would be discussed in almost any good Astronomy book.
MM agrees with the math of what is happening here. But MM has an explanation that provides a few more details. The increased density of the elysium (arising partly from Earth being closer to the Sun, partly from Earth's orbital speed being faster) makes electrons slow in their orbits, as expected for any wave-like entity when its medium gets denser. The slower the electrons move, the slower the body moves. The orbital slowing produces perihelion advance. The spin slowing produces the longer day you mentioned.
<hr height=1 noshade id=quote></BLOCKQUOTE id=quote></font id=quote><font face="Verdana, Arial, Helvetica" size=2 id=quote>
So are you saying that the elysium is acting as a storage medium for the difference, that it is acting like a contracted spring that returns the momentum as the Earth goes around? Do the attractions between the atoms increase slightly and reduce the radius of the Earth?
<BLOCKQUOTE id=quote><font size=2 face="Verdana, Arial, Helvetica" id=quote>quote:<hr height=1 noshade id=quote>
First time I hear that! Can you give some sources?
<hr height=1 noshade id=quote></BLOCKQUOTE id=quote></font id=quote><font face="Verdana, Arial, Helvetica" size=2 id=quote>
The Pushing Gravity book discusses the magnitude of the effect but I imagine it would be discussed in almost any good Astronomy book.
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21 years 10 months ago #3126
by tvanflandern
Replied by tvanflandern on topic Reply from Tom Van Flandern
<BLOCKQUOTE id=quote><font size=2 face="Verdana, Arial, Helvetica" id=quote>quote:<hr height=1 noshade id=quote>[Jeremy]: So are you saying that the elysium is acting as a storage medium for the difference, that it is acting like a contracted spring that returns the momentum as the Earth goes around? Do the attractions between the atoms increase slightly and reduce the radius of the Earth?<hr height=1 noshade id=quote></BLOCKQUOTE id=quote></font id=quote><font face="Verdana, Arial, Helvetica" size=2 id=quote>
Well, that's a good question. When light redshifts in a gravitational potential, that energy must go back into the elysium. So yes, the same must happen to Earth's rotational momentum. The stored energy is more like a higher (or lower) temperature for the elysium than it is like a spring. There is no change in Earth's radius.
<BLOCKQUOTE id=quote><font size=2 face="Verdana, Arial, Helvetica" id=quote>quote:<hr height=1 noshade id=quote>[jacques]: First time I hear that! Can you give some sources?<hr height=1 noshade id=quote></BLOCKQUOTE id=quote></font id=quote><font face="Verdana, Arial, Helvetica" size=2 id=quote>
It's a <b>very</b> small effect. Only atomic clocks can notice. -|Tom|-
Well, that's a good question. When light redshifts in a gravitational potential, that energy must go back into the elysium. So yes, the same must happen to Earth's rotational momentum. The stored energy is more like a higher (or lower) temperature for the elysium than it is like a spring. There is no change in Earth's radius.
<BLOCKQUOTE id=quote><font size=2 face="Verdana, Arial, Helvetica" id=quote>quote:<hr height=1 noshade id=quote>[jacques]: First time I hear that! Can you give some sources?<hr height=1 noshade id=quote></BLOCKQUOTE id=quote></font id=quote><font face="Verdana, Arial, Helvetica" size=2 id=quote>
It's a <b>very</b> small effect. Only atomic clocks can notice. -|Tom|-
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21 years 10 months ago #4699
by Jeremy
Replied by Jeremy on topic Reply from
Interesting, so in principle at least, one should be able to determine
the difference between standard theory and MM by measuring the radius of the Earth as it goes around it's orbit. Relativity says it should contract slightly and MM says no change. I am being facetious of course since the measurement problem would be quite severe to measure such a small change.
One more point of clarification if you don't mind. The Earth's orbital velocity is only speeding up and slowing down relative to the Sun as the point of reference. Is it the case then that the elysium is traveling along with the Sun and that all bodies have a local elysium that they carry along with them?
the difference between standard theory and MM by measuring the radius of the Earth as it goes around it's orbit. Relativity says it should contract slightly and MM says no change. I am being facetious of course since the measurement problem would be quite severe to measure such a small change.
One more point of clarification if you don't mind. The Earth's orbital velocity is only speeding up and slowing down relative to the Sun as the point of reference. Is it the case then that the elysium is traveling along with the Sun and that all bodies have a local elysium that they carry along with them?
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21 years 10 months ago #4700
by tvanflandern
Replied by tvanflandern on topic Reply from Tom Van Flandern
<BLOCKQUOTE id=quote><font size=2 face="Verdana, Arial, Helvetica" id=quote>quote:<hr height=1 noshade id=quote>Is it the case then that the elysium is traveling along with the Sun and that all bodies have a local elysium that they carry along with them?<hr height=1 noshade id=quote></BLOCKQUOTE id=quote></font id=quote><font face="Verdana, Arial, Helvetica" size=2 id=quote>
Yes, that is true. As Lorentzian relativity (LR) describes this, the "local gravity field" for all bodies determines the local frame of rest. -|Tom|-
Yes, that is true. As Lorentzian relativity (LR) describes this, the "local gravity field" for all bodies determines the local frame of rest. -|Tom|-
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