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New Twist on Hubble's Law
- lyndonashmore
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Lyndon
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<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote">
There is an ambiguity in your explanations: With a resonance frequency lower than 30Hz, you are in the conditions of the CREIL effect, replacing the spin flip resonance of the atom of hydrogen by the plasma resonance. Thus energy may be lost, it may be a redshift.
This redshift is however lower than the CREIL redshift because as long as the resonance frequency is lower than around 1 GHz, the exchanged energy is proportional to the frequency. <hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">
No. Electrons in plasma can and do oscillate with SHM.
See
www-pw.physics.uiowa.edu/plasma-wave/tutorial/waves.html
<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote">
The solar system and the bulk of the universe comprises matter which is mostly in the form of a plasma. Plasma is a very hot gas in which the electrons have been s*****ed from atoms to form a gas of negatively charged electrons and positively charged ions. In a fully thermalized, equilibrium state, these electrons and ions would oscillate about their equilibrium positions. However, any perturbation to this equilibrium would displace the charged particles in such a way as to set up electric and magnetic fields which act as restoring forces to the displaced particles. In the simplest example of such a perturbation, the electrons might be offset from the less mobile (because of their mass) ions. The electrons, then, would execute simple harmonic motion about their equilibrium positions. A measure of electric fields in this perturbed plasma would show a strong line or resonance at a particular frequency, called the electron plasma frequency, which is proportional to the square root of the electron number density of the plasma. By measuring this frequency, the electron density of the plasma can be determined. The electron plasma frequency is one of a number of characteristic frequencies of a plasma. <hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">
Electrons that can perform SHM can and do absorb and re emit photons of e-m radiation. This is how photons travel through a medium by being constantly absorbed and re emitted. If the photon frequency is equal to the natural plasma frequency then resonance takes place and the photon absorbed. The energy going to setting the whole plasma into oscillation. However, in IG space the photon frequency is much greater than the plasma frequency (30Hz) and so the photons are always re emitted. However in a sparsely populated plasma such as that in IG space, the electrons will recoil and some of the photon energy is transferred to the recoiling electron. Photon energy less, photon frequency less, wavelength greater ie redshifted.
The increase in wavelength due to recoil is constant for all frequencies and equal to h/mc.
<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote">
In front of the light beam, the atoms absorb energy to be polarized, this energy being integrally returned to the field when its intensity decreases. The energy does not travel faster than light:
- on the contrary, the small fraction of the energy absorbed at the front of a pulse waits that the pulse decreases to restart its travel.
- during the pulse, the polarized atoms radiate (scatter) a field delayed of pi/2, this radiation requiring no energy because the scattered field is much lower than the exciting field, so that, by interference, the emission of this field requires no energy.<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">
But how does this energy travel? It appears that it is firstly in front of the pulse , then it stops till the pulse travels past and then its off to the front of the pulse again. Do you need a second E-m wave for this energy?
Best regards,
Lyndon
lyndon ashmore - bringing cosmology back down to earth.
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<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote">
the photons are always re emitted. However in a sparsely populated plasma such as that in IG space, the electrons will recoil and some of the photon energy is transferred to the recoiling electron.
<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">
Not clear:
You suppose that photons are absorbed and reemitted. Two problems may appear because you do not indicate how the photons are reemitted:
- Is it a spontaneous emission? if yes, light is scattered into all direstions.
- Do you obtain a mixture of incident photons and scattered photons? if yes, the lines are broadened.
The CREIL solves these problems, it is possible that the same process works, but it must be justified.
It appears that it is firstly in front of the pulse , then it stops till the pulse travels past and then its off to the front of the pulse again. Do you need a second E-m wave for this energy?
<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">
No. A fraction of the energy at the front of the pulse is used to dress the atoms. As the dressing of matter disappears at the end of the pulse, the available corresponding energy is returned to the wave.
Pay attention: the energy used to dress the atoms is not quantized. Else, how could the weakest light beams dress all atoms of a big prism? (refraction laws work at all energies).
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